- Getting a head (H) or a tail is an event when we loss a coin
- Getting any of six faces: 1, 2, 3, 4, 5, 6 is an event when we throw a die.
- Getting an ace or a king or a queen is an event when we draw a card from a pack of well-shuffled cards.
Exhaustive
events: The total
number of possible outcomes in a random experiment (or trial) are known as
exhaustive events. For example:
- There are two exhaustive events head (H) and tail(T) when tossing a coin.
- There are six exhaustive events, 1, 2, 3, 4, 5, 6 when we throw a die.
Favourable
events:
The events which cause
the happening of a particular event A, are called the favourable events to the
event A. For example:
- There are three favourable events for the occurrence of an even number (or an odd number) in the throwing of a die.
- When we draw a card from a pack of cards, there are four favourable events for drawing an ace; there are 12 favourable events fo the drawing of a face card (King, queen, jack).
Mutually
exclusive events: Such
events where the occurrence of one rules out the occurrence of the other, are
called mutually exclusive events. For example:
- In a tossing a coin there are two mutually exclusive events, for if the head comes in a trial, then tail cannot come in the same train or vice versa.
- There are 52 mutually exclusive events in drawing a card from a pack of cards.
Equally
likely events: The
events are said to be equally likely if none of them is expected to occur in
preference to other. For example:
- In tossing a coin, there are two equally likely events H and T.
- In tossing a die, there are six equally likely events 1, 2, 3, 4, 5, 6.
Classical
Definition of Probability: If
there are $n$ exhaustive, mutually
exclusive and equally likely events, out of which $m$ are favourable to the
happening of an event A. Then the probability of happening of A, denoted by
P[A], is defined as
$$P[A]=\frac{Favourable~number~of~case}{Exhaustive ~of ~cases}=\frac{m}{n}$$
Example
1. Find the probability of getting an even
number in a throw of a single die.
Solution: Total number of exhaustive cases $n=6$
Total number of favourable cases $m=3$
Required probability $=\frac{m}{n}=\frac{3}{6}=\frac{1}{2}$
Example
2. From a pack of 52 cards, two cards are
drawn at random. Find the chance that one is a king and the other a queen.
Solution: Total number of cases is $n=52C_2$
Since there are 4 kings and 4 queens, so the number of favourable cases is $m = 4C_1 \times 4C_1$
Required Probability $=\frac{m}{n}=\frac{52C_2 \times 52C_2}{52C_2}=\frac{8}{663}$
Exercises:
- In a single throw with two dice. Find the probability of getting a total of 10.
- Two cards are drawn at random from a well-shuffled pack of 52 cards. Find the probability of getting two aces.
- If $n$ biscuit be distributed among $N$ beggars. Find chance that a particular beggar received $r( > n) $ biscuits.
- What is the chance that a year selected at random will cointains 53 saturday?
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