Bivariate Distributions
Joint Distribution function: Let X and Y be two random variables defined on the same probability space (\Omega, \tilde{A}, P[.]). Then (X, Y) is called a two-dimensional random variable. The joint cumulative distribution function or joint distribution function of X and Y, denoted by F_{X,Y}(x,y), is defined as
F_{X,Y}(x,y)= P[X \leq x, Y \leq y]~ \forall x, y \in R
It may be observed that the joint distribution function is a function of two variables and its domain is the xy-plane. Sometimes we write F_{X,Y}(x,y) as F(x,y).
Properties of Joint Distribution function:
P[x_1 <X \leq x_2, y_1<Y\leq y_2]=F(x_2,y_2)-F(x_2,y_1)-F(x_1,y_2)+F(x_1, y_1) \geq 0
2. (a) F(-\infty, y)=\lim_{x \to -\infty} F(x,y)=0 ~\forall y \in R
(b) F(x, -\infty)=\lim_{y \to -\infty}F(x,y)=0 ~\forall x \in R
(c) F(x, -\infty)= \lim_{x\to \infty, y\to \infty}F(x,y)=1
3. F(x, y) is right continuous in each argument i.e.
\lim_{h\to 0_+} F(x+h, y) = lim_{h \to 0_+} F(x, y+h)=F(x, y)
Remark: Any
function of two variables which fails to satisfy one of the above three
conditions is not a joint distribution function.
Example 1. Show
that the bivariate function:
$F(x, y) = \left\{\begin{array}{ll} e^{-(x+y) & \quad x>0, y>0 \\ 0 & \quad otherwise\end{array}\right.
$
is not a joint distribution function.
Solution: $x^2$
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